In a single-phase circuit with a current of 20 A and a voltage of 220 V, what is the real power if the power factor is 78.8%?

In a single-phase circuit with a current of 20 A and a voltage of 220 V, what is the real power if the power factor is 78.8%?

• A. 3467 W
• B. 4000 W
• C. 3500 W
• D. 3000 W

Answer: (A)

To calculate the real power in a single-phase circuit, you use the formula: \[ P = V \times I \times PF \] where \( P \) is the real power in watts, \( V \) is the voltage in volts, \( I \) is the current in amperes, and \( PF \) is the power factor. Given the values: - Voltage (V) = 220 V - Current (I) = 20 A - Power Factor (PF) = 78.8% = 0.788 (when converted from a percentage to a decimal) Now, substituting these values into the formula: \[ P = 220 \, V \times 20 \, A \times 0.788 \] Calculating step-by-step: 1. First, multiply the voltage by the current: \[ 220 \times 20 = 4400 \, VA \, (volt-amperes) \] 2. Then, multiply by the power factor: \[ 4400 \times 0.788 = 3467.2 \, W \] Since we typically round to the nearest whole number in practical applications, this results in approximately 346

To calculate the real power in a single-phase circuit, you use the formula:

[ P = V \times I \times PF ]

where ( P ) is the real power in watts, ( V ) is the voltage in volts, ( I ) is the current in amperes, and ( PF ) is the power factor.

Given the values:

• Voltage (V) = 220 V

• Current (I) = 20 A

• Power Factor (PF) = 78.8% = 0.788 (when converted from a percentage to a decimal)

Now, substituting these values into the formula:

[ P = 220 , V \times 20 , A \times 0.788 ]

Calculating step-by-step:

1. First, multiply the voltage by the current:

[ 220 \times 20 = 4400 , VA , (volt-amperes) ]

2. Then, multiply by the power factor:

[ 4400 \times 0.788 = 3467.2 , W ]

Since we typically round to the nearest whole number in practical applications, this results in approximately 346