If the electric cost is 10 cents per kWh and the resistance is 10 ohms at 110 volts for 2 hours, what is the cost?

If the electric cost is 10 cents per kWh and the resistance is 10 ohms at 110 volts for 2 hours, what is the cost?

• A. 12.5 cents
• B. 24.2 cents
• C. 30 cents
• D. 50 cents

Answer: (B)

To determine the cost of electricity consumed, we first need to calculate the power usage in kilowatt-hours (kWh). Using Ohm’s law, the current (I) can be calculated from the resistance (R) and voltage (V) using the formula: \[ I = \frac{V}{R} = \frac{110 \text{ volts}}{10 \text{ ohms}} = 11 \text{ amps} \] Next, we can calculate the power (P) in watts: \[ P = V \times I = 110 \text{ volts} \times 11 \text{ amps} = 1210 \text{ watts} \] Now, to convert watts to kilowatts: \[ P_{\text{kW}} = \frac{1210 \text{ watts}}{1000} = 1.21 \text{ kW} \] Next, we calculate the energy consumed over 2 hours: \[ \text{Energy (kWh)} = P_{\text{kW}} \times \text{Time (hours)} = 1.21 \text{ kW} \times 2 \text{ hours} = 2.42 \text{

To determine the cost of electricity consumed, we first need to calculate the power usage in kilowatt-hours (kWh).

Using Ohm’s law, the current (I) can be calculated from the resistance (R) and voltage (V) using the formula:

[ I = \frac{V}{R} = \frac{110 \text{ volts}}{10 \text{ ohms}} = 11 \text{ amps} ]

Next, we can calculate the power (P) in watts:

[ P = V \times I = 110 \text{ volts} \times 11 \text{ amps} = 1210 \text{ watts} ]

Now, to convert watts to kilowatts:

[ P_{\text{kW}} = \frac{1210 \text{ watts}}{1000} = 1.21 \text{ kW} ]

Next, we calculate the energy consumed over 2 hours:

[ \text{Energy (kWh)} = P_{\text{kW}} \times \text{Time (hours)} = 1.21 \text{ kW} \times 2 \text{ hours} = 2.42 \text{